ValueError: invalid literal for int() with base 10:

handling ValueError raised by wrong type conversion in Python

try:
    value = int("invalid")
except ValueError:
    print("ValueError: invalid literal for int() with base 10")

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In this code snippet, the variable "value" is being set to the integer representation of the string "invalid." However, "invalid" is not a valid integer, so the int() function will raise a ValueError. The except block catches this error and prints the error message "ValueError: invalid literal for int() with base 10."